SSC TRICKS FOR MATHS

IF SAME NUMBER IS THERE IN A SERIES LIKE 88888 OR 9999 UP TO AS MUCH AS YOU CAN.... IF YOU WANT TO FIND THEIR SUM LETS TAKE AN EXAMPLE 8888+888+88+8=? WE START FROM THE LEFT MULTIPLY 8 BY 1, 2, 3 & 4. U WILL GET YOUR ANSWER THOSE NUMBER WHOSE ALL DIGITS ARE 9 (99)^2=9801 (999)^2=998001 (9999)^2=99980001 (99999)^2=9999800001 THOSE NUMBER WHOSE ALL DIGITS ARE 3 (33)^2=1089                   THOSE NUMBER IN WHICH ALL DIGITS ARE NUMBER IS 3 TWO OR MORE THAN 2 TIMES REPEATED, TO FIND THE SQUARE OF THESE NUMBER,WE REPEAT 1 AND 8 BY (n-1). WHERE n= NUMBER OF TIMES 3 IS REPEATED (333)^2=110889 (3333)^2=11108889 TO CHECK 401 IS A PRIME NUMBER APPROXIMATE SQUARE ROOT = 20 PRIME NO < 20 ARE 2, 3, 5, 7, 11, 13, 17, 19 401 IS NOT DIVISIBLE BY ANY OF THESE PRIME NUMBERS SO 401 IS A PRIME NUMBER.

175 X 157 = ? THE RESULT OF MULTIPLICATION OF THREE DIGIT NUMBER IS 175 X 157 = 27475 STEP 1:  MULTIPLY  (5 X 7) = 35 (NOTE DOWN 5 CARRY 3) STEP 2: THEN DO CROSS MULTIPLICATION (7 X 7 + 5 X 5 + 3 (ADD CARRY)) = 77 (NOTE DOWN 7 CARRY 7) STEP 3: AGAIN (1 X 7 + 1 X 5 + 7 X 5 + 7 (ADD CARRY)) = 54 (NOTE DOWN 4 CARRY 5) STEP 4: DO CROSS MULTIPLICATION AND ADD CARRY  (1 X 5 + 1 X 7 + 5 (ADD CARRY)) = 17 (NOTE DOWN 7 CARRY 1) STEP 5: AGAIN (1 X 1 + 1) = 2, NOTE IT DOWN. AND FINALLY THE RESULT WE GET 27475