SSC TRICKS FOR MATHS

BY SELLING AN ARTICLE AT 2/3 OF THE MARKED PRICE, THERE IS A LOSS OF 10%. THE PROFIT PERCENT, WHEN THE ARTICLE IS SOLD AT THE MARKED PRICE, IS SUPPOSE MARKED PRICE = x THEREFORE, S.P. = Rs 2x/3 C.P. =(2x/3*90)*100 = 20x/27 PROFIT AT MARKED PRICE   = x - 20x/27 = 7x/27 THEREFORE, PERCENT PROFIT   ={(7x/27)/(20x/27)}*100   = 7x/27 * 27/20x * 100 = 35%

THE SPEED OF A MOTOR-BOAT IS THAT OF THE CURRENT OF WATER AS 36:5. THE BOAT GOES ALONG WITH THE CURRENT IN 5 HOURS 10 MINUTES. IT WILL COME BACK IN ? LET THE SPEED OF MOTOR BOAT BE 36x kmph, AND SPEED OF CURRENT = 5x kmph THE BOAT GOES ALONG WITH THE CURRENT IN 5 HOURS 10 MINUTES i. e. 31/6 HOURS THEREFORE,       DISTANCE = 31/6 * (36x + 5x) = (41x * 31) / 6 km, RATE UPSTREAM = 36x - 5x = 31x kmph THEREFORE,         TIME TAKEN = (41x * 31/6) / 31x =41/6 HOURS OR 6 HOURS 50 MINUTES....

SQUARE 1. PERIMETER = 4 * side = 4 * a  WHERE a = SIDE OF SQUARE 2. AREA = (side)^2 3. DIAGONAL = side * sqrt(2) 4. AREA OF THE PATH WHICH IS OUTSIDE OF SQUARE = 4 * (a + x) 5. AREA OF THE PATH WHICH IS INSIDE OF SQUARE = 4 * (a - x) WHERE x = WIDTH OF THE PATH TRAPEZIUM IT IS A QUADRILATERAL WHOSE OPPOSITE SIDES ARE PARALLEL. OTHER TWO OPPOSITE SIDES ARE OBLIQUE. 1. AREA = 1/2 * HEIGHT * (SUM OF PARALLEL SIDES)   HEIGHT IS THE DISTANCE BETWEEN THE TWO PARALLEL SIDES 2. MEDIAN = 1/2 * (SUM OF PARALLEL SIDES) MEDIAN IS THE SEGMENT JOINING THE MIDPOINTS OF OBLIQUE SIDES RHOMBUS IT IS PARALLELOGRAM WHOSE ALL SIDES ARE EQUAL.  ITS DIAGONALS BISECT EACH OTHER AT RIGHT ANGLE. 1. AREA = 1/2 * PRODUCT OF DIAGONALS 2. SIDE = sqrt {(D1/2)^2 + (D2/2)^2} 3. PERIMETER = 4 * SIDE WHERE D1 AND D2 ARE DIAGONALS