SHORTCUTS OF QUANTITATIVE APTITUDE FOR SSC CGL
IF SAME NUMBER IS THERE IN A SERIES LIKE 88888 OR 9999 UP TO AS MUCH AS YOU CAN....
IF YOU WANT TO FIND THEIR SUM
LETS TAKE AN EXAMPLE
8888+888+88+8=?
WE START FROM THE LEFT MULTIPLY 8 BY 1, 2, 3 & 4.
U WILL GET YOUR ANSWER
THOSE NUMBER WHOSE ALL DIGITS ARE 9
(99)^2=9801
(999)^2=998001
(9999)^2=99980001
(99999)^2=9999800001
THOSE NUMBER WHOSE ALL DIGITS ARE 3
(33)^2=1089
THOSE NUMBER IN WHICH ALL DIGITS ARE NUMBER IS 3 TWO OR MORE THAN 2 TIMES REPEATED, TO FIND THE SQUARE OF THESE NUMBER,WE REPEAT 1 AND 8 BY (n-1). WHERE n= NUMBER OF TIMES 3 IS REPEATED
(333)^2=110889
(3333)^2=11108889
TO CHECK 401 IS A PRIME NUMBER
APPROXIMATE SQUARE ROOT = 20
PRIME NO < 20 ARE 2, 3, 5, 7, 11, 13, 17, 19
401 IS NOT DIVISIBLE BY ANY OF THESE PRIME NUMBERS
SO 401 IS A PRIME NUMBER.
IF YOU WANT TO FIND THEIR SUM
LETS TAKE AN EXAMPLE
8888+888+88+8=?
WE START FROM THE LEFT MULTIPLY 8 BY 1, 2, 3 & 4.
U WILL GET YOUR ANSWER
THOSE NUMBER WHOSE ALL DIGITS ARE 9
(99)^2=9801
(999)^2=998001
(9999)^2=99980001
(99999)^2=9999800001
THOSE NUMBER WHOSE ALL DIGITS ARE 3
(33)^2=1089
THOSE NUMBER IN WHICH ALL DIGITS ARE NUMBER IS 3 TWO OR MORE THAN 2 TIMES REPEATED, TO FIND THE SQUARE OF THESE NUMBER,WE REPEAT 1 AND 8 BY (n-1). WHERE n= NUMBER OF TIMES 3 IS REPEATED
(333)^2=110889
(3333)^2=11108889
TO CHECK 401 IS A PRIME NUMBER
APPROXIMATE SQUARE ROOT = 20
PRIME NO < 20 ARE 2, 3, 5, 7, 11, 13, 17, 19
401 IS NOT DIVISIBLE BY ANY OF THESE PRIME NUMBERS
SO 401 IS A PRIME NUMBER.
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