SSC TRICKS FOR MATHS

THERE IS 40% INCREASE IN AN AMOUNT IN 8 YEARS AT SIMPLE INTEREST. WHAT WILL BE THE COMPOUND INTEREST IN RS OF RS 30000 AFTER 2 YEARS AT THE SAME RATE? ACCORDING TO THE QUESTION, IF THE PRINCIPLE = RS 100 THEN INTEREST  = RS 40 THEREFORE RATE = ( I * 100 ) / ( P * T ) = 40 * 100 * 1/100 * 1/8 = 5 % p. a. CASE II, A = P[1+R/100]^T A = 30000[1+5/100]^2 A = 30000[1+1/20]^2 A = 30000 * 21/20 * 21/20 A = RS 33075 THEREFORE, = RS [33075 - 30000] = RS 3075 WHAT IS THE MEASURE OF THE CENTRAL ANGLE OF THE ARC WHOSE LENGTH IS 11 CM AND RADIUS OF THE CIRCLE IS 14 CM? ARC LENGTH IS 11 CM AND IF WE CALCULATE THE CIRCUMFERENCE OF THE CIRCLE, = 2 * pi * r = 2 * 22/7 * 14 = 88 cm AND NOW WE HAVE TO FIND THE ANGLE OF THE ARC, WE KNOW THAT IN A CIRCLE THE ANGLE IN THE MIDDLE IS 360 deg SO, 88cm = 360 deg 1 cm = 360 / 88 AND IN ARC WHICH IS 11 cm, 11 cm = 360/88 * 11 = 45 deg IF THE SHOPKEEPER SELLS AN ITEM AT RS 960 WHICH IS MARKED AS RS 1200, WH

Find the remainder when (3^27) is divided by 5? Firstly we will separate 3^27 like this,               (3^26).3  (it means 3^27 only)  Then, We can also write 3^26 as ((3^2)^13)  We just splitted the power of 3 Now,            {((3^2)^13).3}/5.......... (i)  If we divide 3^2 i.e. 9 by 5 remainder comes to be 4 And that means 4^13 and 4 is less than 5 so remainder again comes to be ( -1) and (-1)^13  means  -1 and in eq (i) 3 is also there left to be divided by 5 and hence there is no power on 3 so  remainder will also be 3  Atlast we have {(-1)*3}/5  -3/5 means 5-3=2 (if there is - sign in the numerator then we have to substract the numerator  from denominator only if numerator is smaller than denominator) So,     2 will be the remainder of this question.  FIND THE REMAINDER WHEN 3^1000 IS DIVIDED BY 7 3^1000 = 3^4 * 3^996 3^996 is divided by 7 and gives the remainder 1  by,  996 = 6k  where 6 is the eulers's number for

MEAN FORMULA:- MEAN = (ADDITION OF f i x i) / f i MEAN FORMULA:- MEAN = a + { (ADDITION OF  f i x i) /  f i} * h a = assumed mean  h = class size MODE FORMULA:- MODE = l + [( f1 - f0) / (2f1 - f0 - f2) ] * h l = lower limit of class of which frequency comes f1 = frequency       f1 = n/2 f0 = preciding f0 f2 = after f0 MEDIAN FORMULA:- MEDIAN = l + {(n/2 - cf) / f} * h l = lower limit of class of which frequency comes n = addition of frequency or last number cumulative frequency h = class size SOME OTHER EXAMPLES ARE: SO MEAN OF THIS QUESTION IS: BY DIRECT METHOD:                             = fixi / fi                             = 3620/140                             = 25.86 BY ASSUMED MEAN METHOD: MEAN = a + fidi/fi              = 25 + 12/140              = 25.86